In this illustration, we will calculate cement, sand, crushed stone, and of course steel for a given water tank. Here in this article today we will discuss how to calculate materials quantity f circular RCC water tank. After reading this article you will be able to know the material estimation of circular RCC water tank.

**Given Data for water Tank**

Here we have two diameters: the external diameter of the tank and the internal diameter of the tank.

External Diameter of water tank = D = 5.30 meter

Internal Diameter of water tank = D1 = 5 meter

Depth of water tank = 3 meter

RCC in base foundation = 30cm =0.30 meter

Slab thickness of water tank = 10cm = 0.10 meter

Wall thickness of tank = 15 cm = 0.15 meter

We used here M15 Grade of Concrete (1:2:4)

Sum of ratio = 1 + 2 + 4 = 7

Use of steel 2% of RCC (Concrete volume)

**Solution**

External diameter of Tank (Total Diameter) = D1 = 5 + 0.15 + 0.15 = 5.3 meter

The internal diameter of the tank = D2 = 5 meters, Here this diameter of the tank is without the 2 wall thickness.

RCC volume of water Tank (wall) = V = Area of RCC work x Depth of tank

Volume = π /4(D² – D1² ) x 3

Volume = π /4 ( 5.30^2 – 5^2) x 3

RCC work Volume = 7.28 m3

Volume of water Tank Slab = Area of Slab x thickness of slab

Volume = π D² / 4 x 0.10 = π /4 x ( 5.3 ^2 ) x 0.10

Volume = 2.206 m3

RCC base foundation volume = Area of foundation x depth of foundation

Volume = π /4 x D² x 0.30

Volume = 3.142 ( 5.3 x 5.3 ) 0.30

Volume = 6.61 m3

Total volume of RCC work = RCC water tank wall volume + water tank slab volume + Foundation RCC volume

Total RCC volume for water tank = 7.28 + 2.206 + 6.61 = 16 m3

Steel Volume for water tank = 2% of RCC volume

Steel volume = 2/100 x 16 = 0.32 m3

**Now Different Materials Quantity**

Total volume of RCC works

Convert Wet RCC volume to Dry materials

Dry volume = wet volume x 1.54 = 16 x 1.54 = 24.64 m3

**Quantity of cement** = proportion of cement / Sum of Proportion x dry volume of Concrete

Quantity of cemtn = 1 / 7 x dry volume = 1 / 7 x 24.64 = 3.52 m3

Convert it to cement bags = Total volume of cement / volume of Cement bag

No’s of Cement bags = 3.52 / 0.0347 = 101.44 say 102 No’s of Bags

**Quantity of Sand** = proportion of Sand / Sum of Proportion x dry volume of Concrete

Quantity of Sand = 2 / 7 x dry volume = 2 / 7 x 24.64 = 7.04 m3

**Quantity of Aggregate** = proportion of aggregate/ Sum of Proportion x dry volume of Concrete

Quantity of Aggregate = 4 / 7 x 24.64 = 14.08 m3

Now Quantity of Steel We Used 2% of RCC Work Volume

Quantity of steel = 2 / 100 x 16 = 0.32 m2

We know that Density of steel = 7850 kg/m3

Weight of Steel = Density of steel x Volume of a steel

Weight of steel = 7850kg/m3 x 0.32 m3= **2512 kgs steel are required for above water tank.**

**Note:** We can also use the same formula to find out the quantity of the material for the rectangular water tank. but there just the Shape is a rectangle and we have to find the volume of the Rectangle shape, just the shape changes, therefore, to find the quantity of the material just used the same formulas which i have discussed in the above water tank.